Chop and replace method??

[Jon Radel]

On 4/4/15 5:58 PM, Nancy Belle wrote:
>>>> sed -i .bak 's/href=\"..\/..\/..\/archival\/archive13\//href=\"/' *.html
>>>>
> Hi Jon Radel
>     
> Oops! I forgot to mention that the *.html files are in different directories and sub-directories. What do I need to add if possible to make sed work with that situation?
So many options.  If you're using sh you could always do the quick and 
dirty:

for i in `find . -name '*html'` ; do sed -i .bak 
's/href=\"..\/..\/..\/archival\/archive13\//href=\"/' $i ; done

while in the directory under which all files you want to change reside.

Polytropon is correct that his version

sed -i .bak 's|href="../../../archival/archive13/|href="|g' *.html

is more readable, and the trailing "g" is important if you have more 
than one href you need to change per line.

to combine things a bit, my current favorite for your problem as I 
currently conceive it is

find . -name '*.html' -execdir sed -i .bak 
's|href="../../../archival/archive13/|href="|g' {} \;

when run from the directory under which all the files live, or you could 
change "find ." to "find <directory>".

List added back in.

--Jon Radel
jon at radel.com

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