OT: UPS for FreeBSD

[Darren Pilgrim]

On 11/29/2014 3:12 PM, Perry Hutchison wrote:
> Presuming a reasonable amount of capacitance on the output,
> a half wave (single diode) rectifier should produce a DC
> output roughly equal to the peak value of the AC input,
> which is indeed ~1.4 * the RMS AC voltage.  A two-diode
> full-wave rectifier using a center tap will also produce DC
> of ~1.4 * the RMS voltage of the entire winding (and with
> the advantage of less ripple).
>
> However, a full wave bridge (4 diodes) should produce a DC
> output roughly equal to the peak-to-peak value of the AC
> input, or ~2.8 * the RMS voltage.

An unloaded, ideal, single-phase FWR produces Vdc = 0.900Vrms.  The 
factor is 2sqrt(2)/pi, to be precise.  A half-wave rectifier produces 
half that.

 From where did you get your figures?