shell script problem
Matthew Seaman
matthew at FreeBSD.org
Sun Dec 23 09:57:27 UTC 2012
On 23/12/2012 09:43, Polytropon wrote:
> On Sun, 23 Dec 2012 10:34:34 +0100, Polytropon wrote:
>> First, the lines with "read" have to be:
>>
>> cat /foo/bar.txt | while read $LINE1
>>
>> cat /foo/bar/foo/bar.txt | while read $LINE2
>>
>> Reason: $LINE1 and $LINE2 will be evaluated here, they are "empty
>> string", causing "read" to throw an error.
>
> Excuse me - I made a mistake! Of course those two lines
> have to be:
>
> cat /foo/bar.txt | while read LINE1
>
> and
>
> cat /foo/bar/foo/bar.txt | while read LINE2
>
> The $ infront of the variable names have to be removed.
> The variable _name_, not its content, has to be provided
> to "read" as a parameter.
>
> The script so far:
>
>
>
> #!/bin/sh
>
> cat foo.txt | while read LINE1
> do
> cat bar.txt | while read LINE2
> do
> if [ "$LINE1" = "$LINE2" ]; then
> sw="1"
> echo "Current value of sw is : " $sw
> break
> fi
> done
> echo "Value of sw is : " $sw
> if [ "$sw" = "0" ]; then
> echo "DO SOMETHING!"
> fi
> sw="0"
> done
>
>
Hmmm.... I'd just like to draw your attention to the comm(1) program,
which lets you find lines common to two files, or only in one or other
of a pair of inputs, very easily. The only slight gotcha is that the
input files have to be sorted.
Cheers,
Matthew
--
Dr Matthew J Seaman MA, D.Phil.
PGP: http://www.infracaninophile.co.uk/pgpkey
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