Value of $? lost in the beginning of a function.

[Romain Tartière]

Hi!

Simple test case:

----8<----------------------
#!/bin/sh
foo()
{
  echo "\$?=$? \$1=$1"
}
false
foo $?
----8<----------------------

% sh foo.sh
$?=0 $1=1
% zsh foo.sh
$?=1 $1=1
% bash foo.sh
$?=1 $1=1

As you can see, the value of $? is « lost » when FreeBSD sh enters a
function.  Is this supposed to behave this way?

Thanks,
Romain

-- 
Romain Tartière <romain at blogreen.org>        http://romain.blogreen.org/
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