* wildcard in.sh script

[Chip Camden]

On Jun 15 2010 17:06, Aiza wrote:
> Aiza wrote:
> >I have a directory with files in it. The first 3 letters of the file 
> >names is the group prefix. I'm trying to write a script to accept the 3 
> >letter of the group followed by a * to mean its a prefix lookup. But 
> >when I run it I get a message "NO match" that is not issued by the 
> >script. Its like * is not allowed as input.
> >
> >Looking for sample .sh code for handling this standard type of lookup or 
> >some online tutorial that has sample code for bourne shell programming.
> >
> 
> 
> 
> Here is the code
> 
>   prefix_name1=$1
>   prefix_name2=`echo -n "${prefix_name1}" | sed 's/*.*$//'`
>   echo "prefix_name1 = ${prefix_name1}"
>   echo "prefix_name2 = ${prefix_name2}"
> 
> 
>   if [ ${prefix_name1} -nq ${prefix_name2} ]; then
>   echo "prefix_name2 = ${prefix_name2}"
>   fi
> exerr "hard stop"
> 
> 
> Here is the test and out put
> # >admin cell*
> admin: No match.
> 

As others have mentioned, you need to quote or escape the * in the
command line:

admin "cell*"

You've also botched your regex (/*.*$/) -- it can't begin with a *.  What exactly
are you trying to match?

-- 
Sterling (Chip) Camden
http://camdensoftware.com | http://chipstips.com | http://chipsquips.com