simple (and stupid) shell scripting question

[Nerius Landys]

> >From the man page:
>
> Command Substitution
> [...]
>  If  the  substitution  appears within double quotes, word splitting and
>       pathname expansion are not performed on the results.
>
> In other words:
>
> sh-4.0$ touch "x y"
> sh-4.0$ for i in `ls`; do echo "$i"; done
> x
> y
> sh-4.0$ for i in "`ls`"; do echo "$i"; done
> x y
> sh-4.0$

But in the case where you're assigning the output of ls directly to a
variable like this:

FOO=`ls`

vs

FOO="`ls`"

the text assigned to FOO is the same, right?

I know that later if you do

for f in $FOO; do
done

it's different from

for f in "$FOO"; do
done

that much is clear.