Using bash with MySQL
carmel_ny
carmel_ny at hotmail.com
Tue Oct 27 15:41:24 UTC 2009
I am in the process of writting a script that will use MySQL as a back
end. For the most part, I have gotten things to work correctly. I am
having one problem though.
Assume a data base:
database: MyDataBase
table: MyTable
field: defaults
Now, I have populated the 'defaults' fields with the declare
statements that I will use in the script. They are entered similar to
this:
declare -a MSRBL_LIST
Now, I issue this from my bash script:
SQL_USER=user # MySQL user
SQL_PASSWORD=secret # MySQL password
DB=MyDataBase # MySQL data base name
HOST=127.0.0.1 # Server to connect to
NO_COLUMN_NAME="--skip-column-names"
COM_LINE="-u${SQL_USER} -p${SQL_PASSWORD} -h ${HOST} ${NO_COLUMN_NAME}"
table=MyTable
DECLARE_STATEMENTS=($(mysql ${COM_LINE} -i -e"use ${DB}; SELECT defaults FROM "${table}" WHERE 1;"))
for (( i=0;i<${#DECLARE_STATEMENTS[*]};i++)); do
echo ${DECLARE_STATEMENTS[i]}
done
This output is produced:
declare
-a
MSRBL_LIST
Obviously, I want the output on one line for each field. I have tried
enclosing the variables with both single and double quote marks;
however, that does not work. Fields that do not contain spaces are
displayed correctly.
Obviously, I am doing something really stupid here. I hope someone can
assist me. I probably should ask this on the MySQL forum; however, I
was hoping that someone here might be able to supply a remedy.
--
Carmel
carmel_ny at hotmail.com
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Fraud is the homage that force pays to reason.
Charles Curtis, "A Commonplace Book"
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