awk question

[Derek Ragona]

You can loop through them using a shell script:
for i in `ls -lt | awk '{if ($8 == 2006) print $9}'`;do rm $i;done

         -Derek


At 06:35 PM 3/5/2007, Gary Kline wrote:

>         Guys,
>
>         Having found $9 , how do I /bin/rm it (using system()--yes??)
>         in an awk one-liner?
>
>         I'm trying to remove from packages from long ago and find and
>         print them with
>
>         ls -lt | awk '{if ($8 == 2006) print $9}';
>
>         but what I want to remove the file pointed at by $9.  I've tried
>         FILE=ARGV[9]; and using FILE within my system() call, but no-joy.
>         What's the magic here?
>
>         thanks in advance,
>
>         gary
>
>
>
>--
>   Gary Kline  kline at thought.org   www.thought.org  Public Service Unix
>
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