simple sh scripting. How to put a result of a command to a variable?

[Michael Conlen]

Constantine wrote:

> Hello!
>
> I am writing a script, which involves unzipping some files. I would 
> have to unzip 4 different zip-files from some directory, and I would 
> need to unzip them to the directory, which would have the same name in 
> it as the original zip-file, i.e. I would like to run something like 
> "ls *.zip", have each file name recorded in some variable, and do a 
> loop like "unzip $filename[$i] -d $filename[$i].unzipped/". Can 
> someone help me with the code? How can I put the results of a command 
> to a variable? 


If I understand you properly I think the following would do what you want

#!/bin/sh
for i in `ls *.zip`
do
    unzip ${i} -d ${i}.unzipped
done