Slow reboots due to ZFS cleanup in kern_shutdown() .. zio_fini()
Peter Eriksson
pen at lysator.liu.se
Mon Dec 2 14:32:44 UTC 2019
I’ve been looking at trying to figure out why our servers take so long to reboot, where the most time is spent doing a “shutdown”. We’ve seen examples where it has taken 10-20 minutes (or more).
This is Dell PowerEdge R730xd servers with 256GB RAM and ~140TB of disks. FreeBSD 11.3. With ~24000 filsystems per server.
We normally cap ARC to 128GB RAM.
Adding a lot of debugging printf() calls to relevant parts of the code points to:
kern_shutdown() ->
EVENTHANDLER_INVOKE(shutdown_post_sync) ->
zfsshutdown() ->
zfs__fini() ->
spa_fini() ->
zio_fini():
Debug output from a test run:
zio_fini: kmem_cache_destroy(zio_buf_cache & zio_data_buf_cache):
kmem_cache_destroy: uma_zfree_arg(0xfffff803465eec00) [zio_buf_12288] took 16 seconds
kmem_cache_destroy(zio_buf_cache[20]) took 16 seconds
kmem_cache_destroy: uma_zfree_arg(0xfffff803465eeb00) [zio_buf_16384] took 61 seconds
kmem_cache_destroy(zio_buf_cache[28]) took 61 seconds
kmem_cache_destroy: uma_zfree_arg(0xfffff8034c9018c0) [zio_buf_131072] took 87 seconds
kmem_cache_destroy(zio_buf_cache[224]) took 87 seconds
kmem_cache_destroy: uma_zfree_arg(0xfffff8034c901880) [zio_data_buf_131072] took 5 seconds
kmem_cache_destroy(zio_data_buf_cache[224]) took 5 seconds
(I modified the code here to print the time spent if it took 2 seconds or more)
This is on a newly rebooted server (with all filesystems mounted). Seems like uma_zfree_arg() is taking really long to execute. Now that code isn’t exactly easy to read (for me atleast)… Lot’s of barrier/locks and stuff.
I wonder why this code should take so long? There shouldn’t be any disk I/O involved and it’s just a cache so I wonder if there might be some way to get rid of it quicker? Any UMA experts online? :-)
Reason for this is that I’d like to be able to make sure a server reboots more quickly in case of problems. Now with the parallell ZFS mount stuff being done at boot time that part is much quicker :-).
- Peter
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