c99/c++ localised variable definition
Paul Richards
paul at originative.co.uk
Mon Jan 31 09:04:34 PST 2005
On Mon, Jan 31, 2005 at 04:58:17PM +0000, Paul Richards wrote:
> On Mon, Jan 31, 2005 at 05:31:17PM +0100, Ulrich Spoerlein wrote:
> > On Mon, 31.01.2005 at 13:36:09 +0100, Poul-Henning Kamp wrote:
> > > >If you carelessly c++-ify a loop like:
> > > >
> > > > for (int i = 0; i < N; i++)
> > > > {
> > > > if (some_condition(i)) break;
> > > > }
> > > > do_something_with(i); /* use finishing index */
> > > >
> > > >you can miss the fact that the value of i is used outside of the
> > > >loop. The newly created scope for "i" shadows the presumably
> > > >pre-existing definition of i at the top of the function, which
> > > >is what do_something_with() gets to see.
> > >
> > > I would _really_ hope we have the compiler warning about this
> > > already ?
> >
> > Doesn't look so:
> > #include <stdlib.h>
> > #include <stdio.h>
> >
> > int
> > main(int argc, char **argv) {
> > int N = 42;
> > int i;
> > for (int i = 0; i < N; i++)
> > if (i == 23)
> > break;
> > printf("%d\n", i); /* use finishing index */
> > return (0);
> > }
> >
> > % cc -Wall -std=c99 test.c && ./a.out
> > 1
>
> gcc should be throwing an uninitialised warning here.
With the right warns it does :-)
cc -Wall -std=c99 -O -Wuninitialized test.c
test.c
test.c: In function `main':
test.c:7: warning: 'i' might be used uninitialized in this function
--
Paul Richards
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