[Bug 278195] daemon in jail is exiting without informing that it failed to execute
- Go to: [ bottom of page ] [ top of archives ] [ this month ]
Date: Sun, 07 Apr 2024 14:44:50 UTC
https://bugs.freebsd.org/bugzilla/show_bug.cgi?id=278195 --- Comment #2 from Zhenlei Huang <zlei@FreeBSD.org> --- > The parent does return 0. The child will complain with "Undefined symbol". truss(1) shows that clearly. ``` # truss -f /tmp/daemon -l daemon echo OK ... 1543: sigaction(SIGHUP,{ SIG_IGN 0x0 ss_t },{ SIG_IGN SA_RESTART ss_t }) = 0 (0x0) 1544: <new process> 1543: fork() = 1544 (0x608) 1544: setsid() = 1544 (0x608) 1544: sigaction(SIGHUP,{ SIG_IGN SA_RESTART ss_t },0x0) = 0 (0x0) 1544: madvise(0x0,0,MADV_PROTECT) = 0 (0x0) 1544: pipe2(0x7fffffffe950,0) = 0 (0x0) ld-elf.so.1: 1544: write(2,"ld-elf.so.1: ",13) = 13 (0xd) /tmp/daemon: Undefined symbol "kqueuex@FBSD_1.7" 1544: write(2,"/tmp/daemon: Undefined symbol "k"...,48) = 48 (0x30) 1544: write(2,"\n",1) = 1 (0x1) 1544: exit(0x1) 1544: process exit, rval = 1 1543: exit(0x0) 1543: process exit, rval = 0 ``` -- You are receiving this mail because: You are the assignee for the bug.